35t^2-18-5=0

Solution for 35t^2-18-5=0 equation:

35t^2-18-5=0

We add all the numbers together, and all the variables

35t^2-23=0

a = 35; b = 0; c = -23;
Δ = b2-4ac
Δ = 02-4·35·(-23)
Δ = 3220
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3220}=\sqrt{4*805}=\sqrt{4}*\sqrt{805}=2\sqrt{805}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{805}}{2*35}=\frac{0-2\sqrt{805}}{70}
=-\frac{2\sqrt{805}}{70}
=-\frac{\sqrt{805}}{35}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{805}}{2*35}=\frac{0+2\sqrt{805}}{70}
=\frac{2\sqrt{805}}{70}
=\frac{\sqrt{805}}{35}
$